Program to find reverse number in C++

In this post we will understand the logic to find the reverse number of a given number, then we will implement the  same in C++ programming language. Let’s understand the logic:

Programming Logic:

• Input a number from the user.
• The while loop is used until n != 0 is false (0).
• In each iteration of the loop, the remainder when n is divided by 10 is calculated and the value of n is reduced by 10 times.
• Inside the loop, the reversed number is computed using:

reverse = reverse*10 + remainder;

Program to find reverse number in C++:

#include<iostream>
using namespace std;

int main() 
{
    int n, rev = 0, remainder;
    cout<<"Input a Number to Reverse and press Enter: ";
    cin>> n; // Taking Input Number in variable number
    while (n != 0) 
    {
        remainder = n % 10;
        rev = rev * 10 + remainder;
        n /= 10;
    }
    cout<<"Reversed Number is: "<<rev;
    return 0;
}

OUTPUT:

Input a Number to Reverse and press Enter: 345

Reversed Number is: 543