Here we will write a program to check where the number is Armstrong number in Python or not. Lets first understand what is an Armstrong number.

A positive integer is called an Armstrong number of order `n` if

abcd... = an + bn + cn + dn + ...

In case of an Armstrong number of 3 digits, the sum of cubes of each digits is equal to the number itself. For example:

153 = 1*1*1 + 5*5*5 + 3*3*3 // 153 is an Armstrong number.

Now we will the the code for the same in Python.

## Python program to check if number is Armstrong Number

# Python program to check if the number provided by the user is an Armstrong number or not # take input from the user # num = int(input("Enter a number: ")) # initialize sum sum = 0 # find the sum of the cube of each digit temp = num while temp > 0: digit = temp % 10 sum += digit ** 3 temp //= 10 # display the result if num == sum: print(num,"is an Armstrong number") else: print(num,"is not an Armstrong number")

### OUTPUT:

Enter a number: 407 407 is an Armstrong number

Comment for any concerns.